I found this question and I was just wondering how you would explain the solution:
If
 = 7)
, which of the following must be true?
I. f is continuous at x=3
II. f is differentiable at x =3.
III. f(3)=7
Thank you,
Michelle
Well, the way I would explain it is to first note
that, in order of strength (something I'd want to
make sure the student knows, so I'd go to the trouble),
we have
II implies I implies III.
Thus, an efficient strategy (something I'd also want
a student to know) would be to first see if III can
fail. Since III is the weakest, if III fails, then
the other two will fail for the same example. If you
can't get III to fail, then see if I can fail, because
II will also fail for the same example. If you can't
get I to fail, then see if you can get II to fail.
Doing this will give you a lower bound on what can
fail. [Whatever example(s) you have in hand, if any,
will definitely show things that don't have to be
true. However, there might be more things that don't
have to be true than you were able to uncover.] To
get an upper bound on what can fail (which hopefully
will be the same as the lower bound you got, so that
you can answer the question), go back and see if any
of the reverse implications can be established with
what is given. Of course, if all three fail for your
example, then this step isn't needed.
As to the particulars at hand in the problem you
gave, it's of course easy to get an example where
III fails. [Just consider a function whose value at
x = 3 isn't equal to its limit at x = 3. For example,
f(x) = 7 for all x not equal to 3 and f(3) = 8.]
Dave L. Renfro